[leetcode][sql] filtering&aggregation
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# Write your MySQL query statement below
# 조건
# ORDER BY COUNT(customer_number) DESC LIMIT 1
SELECT customer_number
FROM Orders
GROUP BY customer_number
ORDER BY COUNT(*) DESC
LIMIT 1;
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SELECT customer_number
FROM Orders
GROUP BY customer_number
HAVING COUNT(*) = (
SELECT MAX(order_count)
FROM (
SELECT COUNT(*) as order_count
FROM Orders
GROUP BY customer_number
) as counts
);
#leetcode #sql #groupby #orderbycountDescLimit
이 기사는 저작권자의 CC BY 4.0 라이센스를 따릅니다.


