[leetcode][sql] leftJoin - on - where - orderby-
Employees Whose Manager Left the Company
1
2
3
4
5
6
7
8
9
10
11
# Write your MySQL query statement below
# 조건:
# 급여가 30000미만
# 매니저가 회사를 떠남(manager_id는 있지만 해당 employee_id가 테이블에 없음)
SELECT e1.employee_id
FROM Employees e1
LEFT JOIN Employees e2 ON e1.manager_id = e2.employee_id
WHERE e1.salary < 30000
AND e1.manager_id IS NOT NULL -- 매니저가 있어야 함
AND e2.employee_id IS NULL -- 하지만 매니저 정보는 없어야 함
ORDER BY e1.employee_id;
#leetcode #sql #leftjoin
이 기사는 저작권자의 CC BY 4.0 라이센스를 따릅니다.

